Sudoku zabójca №316190

In this Sudoku, an interesting combination of four cells with the sum of 28 was formed. Moreover, one of the cells made a pair with the other cell, which is not included in these 4, with the sum 6.
That is, the permissible values of this cell are 1, 2, 4, 5. The first two values disappear, since in this case the sum of the remaining three cells will be 27 or 26. It is known that the maximum sum of 3 values is 7 + 8 + 9 = 24.
But 4 and 5 are quite good , and come up to triples with amounts of 24 and 23, respectively.
As a result, the decision was reduced to considering alternatives 4 7 8 9 and 5 6 8 9.